NAME

std::chrono::duration_cast - std::chrono::duration_cast

Synopsis

Defined in header <chrono>
template <class ToDuration, class Rep, class Period>
constexpr ToDuration duration_cast(const (since C++11)
std::chrono::duration<Rep,Period>& d);

Converts a std::chrono::duration to a duration of different type ToDuration.

The function does not participate in overload resolution unless ToDuration is a
specialization of std::chrono::duration.

No implicit conversions are used. Multiplications and divisions are avoided where
possible, if it is known at compile time that one or more parameters are 1.
Computations are done in the widest type available and converted, as if by
static_cast, to the result type only when finished.

Parameters

d - duration to convert

Return value

d converted to a duration of type ToDuration.

Notes

Casting between integer durations where the source period is exactly divisible by
the target period (e.g. hours to minutes) or between floating-point durations can be
performed with ordinary casts or implicitly via std::chrono::duration constructors,
no duration_cast is needed.

Casting from a floating-point duration to an integer duration is subject to
undefined behavior when the floating-point value is NaN, infinity, or too large to
be representable by the target's integer type. Otherwise, casting to an integer
duration is subject to truncation as with any static_cast to an integer type.

Example

This example measures the execution time of a function

// Run this code

#include <iostream>
#include <chrono>
#include <ratio>
#include <thread>

void f()
{
std::this_thread::sleep_for(std::chrono::seconds(1));
}

int main()
{
auto t1 = std::chrono::high_resolution_clock::now();
f();
auto t2 = std::chrono::high_resolution_clock::now();

// floating-point duration: no duration_cast needed
std::chrono::duration<double, std::milli> fp_ms = t2 - t1;

// integral duration: requires duration_cast
auto int_ms = std::chrono::duration_cast<std::chrono::milliseconds>(t2 - t1);

// converting integral duration to integral duration of shorter divisible time unit:
// no duration_cast needed
std::chrono::duration<long, std::micro> int_usec = int_ms;

std::cout << "f() took " << fp_ms.count() << " ms, "
<< "or " << int_ms.count() << " whole milliseconds "
<< "(which is " << int_usec.count() << " whole microseconds)" << std::endl;
}

Possible output:

f() took 1000.23 ms, or 1000 whole milliseconds (which is 1000000 whole microseconds)