NAME

std::is_compound - std::is_compound

Synopsis

Defined in header <type_traits>
template< class T > (since C++11)
struct is_compound;

If T is a compound type (that is, array, function, object pointer, function pointer,
member object pointer, member function pointer, reference, class, union, or
enumeration, including any cv-qualified variants), provides the member constant
value equal true. For any other type, value is false.

The behavior of a program that adds specializations for is_compound
or is_compound_v
(since C++17) is undefined.

Template parameters

T - a type to check

Helper variable template

template< class T > (since C++17)
inline constexpr bool is_compound_v = is_compound<T>::value;

Inherited from std::integral_constant

Member constants

value true if T is a compound type , false otherwise
[static] (public static member constant)

Member functions

operator bool converts the object to bool, returns value
(public member function)
operator() returns value
(C++14) (public member function)

Member types

Type Definition
value_type bool
type std::integral_constant<bool, value>

Notes

Compound types are the types that are constructed from fundamental types. Any C++
type is either fundamental or compound.

Possible implementation

template< class T >
struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {};

Example

// Run this code

#include <iostream>
#include <type_traits>

int main() {
class cls {};
std::cout << (std::is_compound<cls>::value
? "`cls` is compound"
: "`cls` is not a compound") << '\n';
std::cout << (std::is_compound_v<int>
? "`int` is compound"
: "`int` is not a compound") << '\n';
}

Output:

`cls` is compound
`int` is not a compound

See also

is_fundamental checks if a type is a fundamental type
(C++11) (class template)
is_scalar checks if a type is a scalar type
(C++11) (class template)
is_object checks if a type is an object type
(C++11) (class template)
is_array checks if a type is an array type
(C++11) (class template)