NAME

std::is_standard_layout - std::is_standard_layout

Synopsis

Defined in header <type_traits>
template< class T > (since C++11)
struct is_standard_layout;

If T is a standard-layout type, provides the member constant value equal to true.
For any other type, value is false.

The behavior is undefined if std::remove_all_extents_t<T> is an incomplete type and
not (possibly cv-qualified) void.

The behavior of a program that adds specializations for is_standard_layout
or is_standard_layout_v
(since C++17) is undefined.

Template parameters

T - a type to check

Helper variable template

template< class T >
inline constexpr bool is_standard_layout_v = (since C++17)
is_standard_layout<T>::value;

Inherited from std::integral_constant

Member constants

value true if T is a standard-layout type , false otherwise
[static] (public static member constant)

Member functions

operator bool converts the object to bool, returns value
(public member function)
operator() returns value
(C++14) (public member function)

Member types

Type Definition
value_type bool
type std::integral_constant<bool, value>

Notes

A pointer to a standard-layout class may be converted (with reinterpret_cast) to a
pointer to its first non-static data member and vice versa.

If a standard-layout union holds two or more standard-layout structs, it is
permitted to inspect the common initial part of them.

The macro offsetof is only guaranteed to be usable with standard-layout classes.

Example

// Run this code

#include <iostream>
#include <type_traits>

struct A
{
int m;
};

struct B
{
int m1;
private:
int m2;
};

struct C
{
virtual void foo();
};

int main()
{
std::cout << std::boolalpha;
std::cout << std::is_standard_layout<A>::value << '\n';
std::cout << std::is_standard_layout<B>::value << '\n';
std::cout << std::is_standard_layout<C>::value << '\n';
}

Output:

true
false
false